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Question

A cylindrical wire of radius 0.5mm and conductivity 5×107 S/m is subjected to an electric field of 10 mV/m. The expected value of current in the wire will be x3π mA. The value of x is

A
5.00
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B
5
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C
5.0
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Solution

As we know that,
J=σE J=5×107×10×103

J=50×104 A/m2

Current from wire is,
I=J×πR2 I=50×104×π×(0.5×103)2 A

I=125×103×π A

I=(5)3π mA

x=5

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