A cylindrical wire of radius 0.5mm and conductivity 5×107S/m is subjected to an electric field of 10mV/m. The expected value of current in the wire will be x3πmA. The value of x is
A
5.00
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B
5
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C
5.0
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Solution
As we know that, J=σE⇒J=5×107×10×10−3
⇒J=50×104A/m2
Current from wire is, I=J×πR2⇒I=50×104×π×(0.5×10−3)2A