Question

A d-block element forms octahedral complex, but its spin magnetic moment remains same either in strong field or in weak field ligand. Which of the following is/are correct ?

• A. Element always forms colorless compound.
• B. Number of electrons in t${}_{2g}$ orbitals are higher than in e${}_g$ orbitals.
• C. It can have either d${}^3$ or d${}^8$ configuration.
• D. It can have either d${}^7$ or d${}^8$ configuration.

Answer 1

Answer: (B), (C)

The correct options are
B Number of electrons in t${}_{2g}$ orbitals are higher than in e${}_g$ orbitals.
C It can have either d${}^3$ or d${}^8$ configuration.

Option (B), (C) are correct.

(A): Element always forms both colorless and coloured compound.

(B) : Number of electrons in $t_{2}g$ orbitals are higher than in $e_g$ orbitals.

(C) : It can have either$d_3$ or $d_8$ configuration.

(D): It does not have either $d^7$ or $d^8$ configuration.

In octahedral complexes, the oxidation state of the metal also determines how small or large ${△}_o$ is. The higher the oxidation state of the metal, the stronger the ligand field that is created. In the event that there are two metals with the same d electron configuration, the one with the higher oxidation state is more likely to be low spin than the one with the lower oxidation state.

Usually, the field strength of the ligand, which is also determined by large or small ${△}_o$, determines whether an octahedral complex is high or low spin.