A D.M.M is in tan A position in a region where $B_{H}$ is 50 $μ$ T. When a magnet is placed at a suitable distance the deflection obtained is 45 $^{0}$ . The resultant magnetic field at the centre of the compass is

μ

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50 \sqrt{2} μ ⊤

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100

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Solution

The correct option is A $50 \sqrt{2} μ ⊤$
The magnetic field due to the magnet is B $= B_{H} t a n θ$
$B = B_{H} t a n 45 = B_{H}$
Total magnetis field at the centre is
$B_{T} = \sqrt{B^{2} + B_{H}^{2}} = \sqrt{2} B_{H}$
$B_{T} = 50 \sqrt{2} μ$ T

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A D.M.M is in tan A position in a region where BH is 50μT. When a magnet is placed at a suitable distance the deflection obtained is 450. The resultant magnetic field at the centre of the compass is

The correct option is A 50√2μ⊤The magnetic field due to the magnet is B =BHtanθB=BHtan45=BHTotal magnetis field at the centre is BT=√B2+B2H=√2BHBT=50√2μT

A D.M.M is in tan A position in a region where $B_{H}$ is 50 $μ$ T. When a magnet is placed at a suitable distance the deflection obtained is 45 $^{0}$ . The resultant magnetic field at the centre of the compass is

The correct option is A $50 \sqrt{2} μ ⊤$
The magnetic field due to the magnet is B $= B_{H} t a n θ$
$B = B_{H} t a n 45 = B_{H}$
Total magnetis field at the centre is
$B_{T} = \sqrt{B^{2} + B_{H}^{2}} = \sqrt{2} B_{H}$
$B_{T} = 50 \sqrt{2} μ$ T