Question

A dancer demonstrating dance steps along a straight line. The position time graph $(x-t)$ is as shown in the given figure. Find the average velocity of the dancer during time interval between $t=4.5s$ to $t=9s$.

• A. $1m{s}^{-1}$
• B. $-1.33m{s}^{-1}$
• C. $2.75m{s}^{-1}$
• D. $-0.89m{s}^{-1}$

Answer 1

The correct option is D $-0.89m{s}^{-1}$

$\frac{finalposition-initialposition}{totaltime}=$ average velocity

Initial position $x=4$
Final position $y=0$
Total time $=4.5s$

So average velocity $=\frac{0-4}{4.5}$ $=-0.89m/s$.