A daniel cell is balanced on 125 cm length of a potentiometer wire. When the cell is short circuited with a 2Ωresistance, the balancing length obtained is 100 cm. Internal resistance of the cell will be
A
1.5Ω
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B
0.5Ω
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C
1.25Ω
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D
45Ω
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Solution
The correct option is B0.5Ω By using r=l1−l2l2×R′⇒r=125−100100×2=12=0.5Ω