Question

A dart is thrown horizontally with an initial speed of 10 m/s towards point P, the bull's eye on a dart board. It hits at the point Q on the rim, vertically below P, 0.2 seconds later, what is distance PQ?

• A. 0.1 m
• B. 0.2 m
• C. 0.3 m
• D. 0.05 m

Answer 1

The correct option is B

0.2 m

Consider Vertical motion of dart
$u_y=0a_y=-gs=ut+\frac{1}{2}a{t}^{2}t=0.2secs=0-\frac{1}{2}\times 10\times 0.2\times 0.2s=-0.2m.$