A dealer bought $100$ footballs for $₹ 40$ each. He sells $20 %$ of them at a gain of $10 %$ . At what gain per cent must he sell the remaining so as to gain $25 %$ on whole.

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Solution

Number of footballs = $100$
cost price of a football = $₹ 40$
Total cost Price = $40 \times 100 = ₹ 4000$
$20 % o f 100 f o o t b a l l s = 20$
Selling Price of Each for $20 = 40 + \frac{10}{100} \times 40 = ₹ 44$
Selling Price of $20 = 44 \times 20 = ₹ 880$
Total Gain = $25 %$
Total selling price = $4000 + \frac{25}{100} \times 4000 = ₹ 5000$
Selling price of remaining $80 f o o t b a l l s = 5000 - 880 = ₹ 4120$
Cost Price of remaining $80 f o o t b a l l s = 80 \times 40 = ₹ 3200$
$g a i n = 4120 - 3200 = ₹ 920 G a i n % = \frac{920}{3200} \times 100 = \frac{115}{4} % = 28.75 %$
Hence he sell the remaining footballs on a gain of $28.75 %$

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A dealer bought 100 footballs for ₹40 each. He sells 20%of them at a gain of 10%. At what gain per cent must he sell the remaining so as to gain 25% on whole.

A dealer bought $100$ footballs for $₹ 40$ each. He sells $20 %$ of them at a gain of $10 %$ . At what gain per cent must he sell the remaining so as to gain $25 %$ on whole.