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Question

A dealer bought two tables for Rs 3120. He sold one of them at a loss of 15% and other at a gain of 36%. Then, he found that each table was sold for the same price. Find the cost price of each table.


Solution

Given that the selling price is same for both the tables.Let the C.P of 1 table be Rs. x, then the C.P of the other will be Rs.3120-x.Loss on the first table= 15%Therefore, S.P=C.P100-loss%100 S.P= 85x100=Rs. 0.85xGain on the second table = 36% Therefore, S.P =C.P100+gain%100S.P=Rs. 1.363120-xSince both tables have the same S.P,So, 0.85x=1.363120-x0.85x=4243.20-1.36x2.21x=4243.20 x =4243.202.21 x=Rs. 1920So,the cost price of the first table is Rs. 1920. Cost price of the second table = Rs. ( 3120-1920)=Rs. 1200

Mathematics
RD Sharma (2019, 2020)
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