Question

A dealer gets ₹ 940 more if instead of selling a table at a loss of 10%, it is sold at a gain of 10%. Find the cost price of the table.

Answer 1

Let the cost price be ₹x.
Loss = 10% of ₹x = $\frac{10}{100}x=₹\frac{x}{10}$
SP in case of loss = CP − Loss = $x-\frac{x}{10}=₹\frac{9x}{10}$
Gain =10% of ₹x = $\frac{10}{100}x=₹\frac{x}{10}$
SP in case of profit = CP + Profit = $x+\frac{x}{10}=₹\frac{11x}{10}$
It is given that dealer gets ₹940 more if sold at a profit of 10% instead of loss of 10%.
∴ SP in case of profit − SP in case of loss = ₹940
$$\begin{gathered} \Rightarrow \frac{11x}{10}-\frac{9x}{10}=940 \\ \Rightarrow \frac{2x}{10}=940 \\ \Rightarrow x=4700 \end{gathered}$$
Hence, the cost price of the table is ₹4,700.