A dealer makes a profit of $9$ $%$ by selling a camera for $R s .$ $3379$ . Find the cost price of the camera.

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Solution

Given,

Profit $% = 9 %$

selling price $= R s .3379 .$

To find $\to$ cost price
Let the CP be $x$

$P r o f i t % =$ $\frac{s e l l i n g p r i c e - c o s t p r i c e}{c o s t p r i c e} \times 100 %$

$\Rightarrow 9 = \frac{3379 - x}{x} \times 100$

$\Rightarrow 9 x = 337900 - 100 x$

$\Rightarrow 109 x = 337900$

$\Rightarrow x = \frac{337900}{109}$

$\Rightarrow x = 3100$

Hence, the cost price is $R s . 3100$

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A dealer makes a profit of 9 % by selling a camera for Rs. 3379. Find the cost price of the camera.

Given,Profit %=9%selling price =Rs.3379.To find → cost priceLet the CP be xProfit%= sellingprice−costpricecostprice×100%⇒9=3379−xx×100⇒9x=337900−100x⇒109x=337900⇒x=337900109⇒x=3100Hence, the cost price is Rs.3100

A dealer makes a profit of $9$ $%$ by selling a camera for $R s .$ $3379$ . Find the cost price of the camera.