Question

A dealer marks his goods $40$% above the cost price and allows a discount $10$%. Find the profit percent.

Answer 1

Let the C.P. be $x$ Rs
The marked price = $x+\frac{40x}{100}=\frac{140x}{100}$ Rs
[ Discount = $10\%=\frac{10x}{100}$]
If M.P is $\frac{140x}{100}$ Rs, then S.P = $\frac{140x}{100}-\frac{10}{100}\times \frac{140x}{100}=\frac{126x}{100}$
C.P = $x$ Rs, S.P = $\frac{126x}{100}$ Rs,
S.P > C.P.
Therefore, there is a profit.
Profit $=$ S.P $-$ C.P
$=\frac{126x}{100}-x=\frac{26x}{100}$ Rs

Profit $\%=\frac{(profit\times 100)}{x}=\frac{26x}{100x}\times 100=26\%$

Hence, the answer is $26\%$