A dealer sells an article at 5% higher price.If the article is purchased at 10% less cost and sold for Rs.156 less than there is a profit of 15%. Find the cost price of the article.

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Solution

Suppose the $C o s t P r i c e$ of the article is $R s .100 .$
$S e l l i n g P r i c e$ (at $5 %$ higher price) $= R s . 105$

If it is purchased at $10 %$ less $C P^{'} = 100 - 10 = R s . 90$
at $15 %$ profit,
$S P^{'}$ = $90 \times \frac{100 + 15}{100} = 90 \times \frac{115}{100} = R s .103 .50$
Difference in the two selling price $= 105 - 103.50 = R s .1 .50$
$∵$ If the difference in the $S . P$ is $R s .1 .50$ then the $C P$ is $R s .100$
$∴$ If the difference in the $S . P$ is $R s . 156$ then the $C P$ is $\frac{100}{1.50} \times 156 = R s . 10400$

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