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Question

A dealer sells an article for Rs.75 and gains as much per cent as the cost price of the article. Find the cost price of the article.

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Solution

SP=75 Rs.
Let the profit% is x%.
So the cost price is x Rs.

Profit= SP- CP
= 75-x Rs.


Profit%= open parentheses fraction numerator p r o f i t over denominator C P end fraction close parentheses×100
x=fraction numerator 75 minus x over denominator x end fraction ×100
x2=(75x)×100
x2=7500100x
x2+100x7500=0
x2+150x50x7500=0
x(x+150)50(x+150)=0
(x50)(x+150)=0

Either
x-50=0
x=50

Or
x+150=0
x=-150 coz the value of x cannot be 0 we'll discard this value.

Hence the cost price is Rs 50
And profit% is 50%


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