Question

A dealer sold a VCR and a TV for $Rs.38560$ making profit of $12$% on VCR and $15$% on TV. By selling them for $Rs.38620$, he would have realised a profit of $15$% on VCR and $12$% on TV. Find the cost price of each

• A. CP of VCR $=Rs.15000$ and CP of TV $=Rs.17000$
• B. CP of VCR $=Rs.21000$ and CP of TV $=Rs.32000$
• C. CP of VCR $=Rs.18000$ and CP of TV $=Rs.16000$
• D. CP of VCR $=Rs.12000$ and CP of TV $=Rs.15000$

Answer 1

Answer: (C)

CP of VCR $=Rs.18000$ and CP of TV $=Rs.16000$

Let CP of VCR be $Rs.x$ and C.P of TV be $Rs.y$
According to problem
$\frac{112}{100}x+\frac{115}{100}y=\mathrm{38560.......}\left(i\right)$
and $\frac{115}{100}x+\frac{112}{100}y=\mathrm{38620.......}\left(ii\right)$
Solving equation $\left(i\right)$ and $\left(ii\right)$ $x=Rs.18000$ and $y=Rs.16000$. So, CP of VCR $=Rs.18000$ and CP of TV $=Rs.16000$