A decapeptide (MW = 796) on complete hydrolysis gives glycine (MW = 75), alanine and phenylalanine. Glycine contributes 47.0 % of the total weight of the hydrolyzed products. The number of glycine units present in the decapeptide is:

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Solution

The correct option is A 6
M.wt of Decapeptide $= 796 g / m o l$
Total bonds to be hydrolysed $= (10 - 1) = 9$ per molecule.

Total weight of $H_{2} O$ added $= 9 \times 18 = 162 g / m o l .$

Total wt. of hydrolysis product $= 796 + 162 = 958 g$

Total wt. of glycine in product $= \frac{958 \times 47}{100} g = 450 g$

Molecular wt. of glycine $= 75 g / m o l$ .

Number of glycine $= \frac{450}{75} = 6$ .

Hence, the correct option is $A$

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