The correct option is B π=7.38 atm
K4Fe(CN)6⇌4K++[Fe(CN)6]4−
As one molecule of potassium ferrocyanide dissociates into five particles.
So, n=5
Degree of dissociation, α=50%=0.5
For dissociation,
α=i−1n−1
0.5=i−15−1
i=3
Osmotic pressure, (π)=iCRT
Given:
Concentration, C=110 mol L−1
R=0.082 L atm mol−1 K−1
T=300 K
π=3×1×0.082×30010π=7.38 atm