Question

A decimolar solution of potassium ferrocyanide is $50\%$ dissociated at $300$K. Calculate the osmotic pressure of the solution. $(R=8.314K{J}^{-1}mo{l}^{-1})$

Answer 1

When potassium ferrocyanide dissociates it gives two product, n=2.

$\beta =\frac{i-1}{\frac{1}{n}-1}$

$\beta =$degree of dissociation

$i=$Van't Hoff factor

$0.5=\frac{i-1}{\frac{1}{2}-1}$

$i=0.75$

$\pi =iCRT=0.75\times 8.314\times 300=187.065J/L=1.847atm$

Osmotic pressure is 1.847 atm.