(a) Define (i) oxidation, and (ii) reduction.
(b) Identify the substances oxidised and reduced in the chemical reaction:
MnO₂ + 4HCl → MnCl₂+ Cl₂+ 2H₂O

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Solution

(a)
(i) Oxidation: Addition of oxygen, removal of hydrogen and loss of electrons is known as oxidation.
Reduction: Addition of hydrogen, removal of oxygen and gain of electrons is known as reduction.

(ii)

MnO₂ changes to MnCl₂, here Mn loses oxygen, so it is reduction.
HCl changes to Cl₂, here Cl loses hydrogen, so it is oxidation.

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Q. In the reaction

\to

M N O_{2} + 4 H C L \to M n C l_{2} + 2 H_{2} O + C l_{2}

(a) name the compound (i) oxidised (ii) reduced
(b) define oxidation of reduction on its basis.

Identify the substance oxidized, substance reduced, oxidising agent and reducing agent.
$M n O_{2}$ + $4 H C l$ $\to$ $M n {C l}_{2}$ + $2 H_{2} O$ + ${C l}_{2}$ .

Q. Identify the substance oxidized,substance reduced ,oxidizing agent and reducing agent :

M n O_{2} + 4 H C L \to M n C l_{2} + 2 H_{2} O + C l_{2}

Q. State which substance is getting oxidised and reduced in the following equation:
MnO₂+ 4HCl -> MnCl₂+ 2H₂O + Cl₂

Q. Which substance/ion is oxidised and which substance/ion is reduced in the following reaction?

M n O_{2} + 4 H C l \to M n C l_{2} + 2 H_{2} O + C l_{2}

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(a) Define (i) oxidation, and (ii) reduction. (b) Identify the substances oxidised and reduced in the chemical reaction: MnO2 + 4HCl → MnCl2 ​+ Cl2 + 2H2O

(a) Define (i) oxidation, and (ii) reduction.
(b) Identify the substances oxidised and reduced in the chemical reaction:
MnO₂ + 4HCl → MnCl₂+ Cl₂+ 2H₂O