(b) The resistance of a wire can be represented by the following equation:
So, when the conductor is made thinner, its area of cross-section will decrease, since resistance is inversely proportional to the area of the conductor. Therefore, its resistance will increase.
(c) We know that V = IR
If V is constant, resistance is doubled R' = 2R.
Then V' = I'R'
V' = V since V is constant
Thus, the current will get reduced to half.