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Question

A deflection magnetometer is arranged in tanA position. When a bar magnet is placed deflection is observed to be 'θ' and period of oscillation of the needle is ‘X’. When the magnet is removed and magnetic needle is made to oscillate in presence of earth’s magnetic field then its period is ‘Y’, then XY is


A
tanθ
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B
cosθ
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C
sinθ
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D
cosθ
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Solution

The correct option is A cosθ
τ=MBθ=Iα=>α=ω2θ
ωBres
X=k/Bres,Y=k/BH
X/Y=BH/Bres
Bres=BHsecθ(sinceBr=B2H+B2)
X/Y=cosθ

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