A deflection magnetometer works on

Coulomb's law

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Tangent law

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Curie law

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The law of vibration of a magnet

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Solution

The correct option is B Tangent law
A deflection magnetometer works on the tangent law in which the two magnetic fields are perpendicular to each other, these fields are earth's magnetic field in $N - S$ direction and field of a given magnet in $E - W$ direction.

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Similar questions

Q. In deflection magnetometer, to find dipole moment

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Q. With a standard rectangular bar magnet 'the time period of a vibration magnetometer is

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In the working of deflection magnetometer, the deflection can never be :

In an experiment with vibration magneto-meter the value of $4 π^{2} \frac{I}{T^{2}}$ for a short bar magnet is observed as $36 \times 10^{- 4}$ . In the experiment with deflection magnetometer with the same magnet the value of $\frac{4 π d^{3}}{2 μ_{0}}$ is observed as $\frac{10^{8}}{36}$ . The magnetic moment of the magnet used is :

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A deflection magnetometer works on

The correct option is B Tangent lawA deflection magnetometer works on the tangent law in which the two magnetic fields are perpendicular to each other, these fields are earth's magnetic field in N−S direction and field of a given magnet in E−W direction.

The correct option is B Tangent law
A deflection magnetometer works on the tangent law in which the two magnetic fields are perpendicular to each other, these fields are earth's magnetic field in $N - S$ direction and field of a given magnet in $E - W$ direction.