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Question

(a) Derive the relation between commercial unit of energy (kWh) and SI unit of energy (joule).
(b) A certain household consumes 650 units of electricity in a month. How much is this electricity in joules?

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Solution

(a) Commercial unit of energy in 1 kWh. One kilowatt-hour is the amount of energy consumed in one hour at a constant rate of one kilowatt. SI unit of energy is joule.

1 kWh= 1 kW × 1 h = 1000 W × 1 h =1000(Js) × 3600 s ( 1 W = 1 Js) = 3600000 J 1 kWh= 3.6×106 J

(b) Energy consumed by certain household = 650 units = 650 kWh

1 kWh= 3.6×106 J

650 kWh= 650×3.6×106 J=2.34×109 J


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