Question

A descending gradient of 4% meets an ascending grade of 1 in 40 where a valley curve of length 200 m is to be formed.The distance of the lowest point on the valley curve from its first tangent point will be

• A. $106.42m$
• B. $110.94m$
• C. $118.94m$
• D. $123.08m$

Answer 1

The correct option is B $110.94m$

$x=W{\left(\frac{n_1}{2N}\right)}^{0.5};N=|n_1+n_2|=|\frac{4}{100}-\frac{1}{40}|=0.065$ $x=200{\left(\frac{0.04}{2\times 0.065}\right)}^{0.5}$
$=110.94m$