Question

A designer produced an image for a banner. He later realized he has made an error .So, he increased its size .The designer increases the size of the image by $112.5\%$ to $18$ inches tall by $22.5$ inches wide. What was the size of the original image?

• A. $15$ inches by $17.5$ inches
• B. $15$ inches by $18$ inches
• C. $16$ inches by $18.5$ inches
• D. $16$ inches by $20$ inches

Answer 1

The correct option is D $16$ inches by $20$ inches

Let original image be $x$ inches tall by $y$ inches wide.

Area of original image $=xy$

Given that,

On an increase of $112.5\%$ of the size, new size $=18\times 22.5$

Area of new image $=405$ in${}^2$

$\Rightarrow 405=\frac{112.5}{100}xy$

$\therefore xy=320$

Option $D)$ satisfies.