Question

A detergent $\left(C_{14}{H}_{29}S{O}_4^{-}N{a}^{+}\right)$ solution becomes a colloidal sol.at a concentration of ${10}^{-3}$ M on an average ${10}^{15}$ colloidal particles are present in $100m{m}^3$ . What is the average number of ions that are contained in one colloidal particle (micelle)? $(N_A=6\times {10}^{23})$

Answer 1

$100m{m}^2$ contain ${10}^{-3}M\times 6\times {10}^{\text{23}}$ Molecules.

$1m{m}^3$ contain $\frac{6\times {10}^{\text{23.3}}}{10}$ Molecules.

$1m{m}^3$ contain $6\times {10}^{\text{18}}$ molecules.

No. fo ion in one colloidal particles is $\frac{6\times {10}^{\text{18}}}{{10}^{\text{15}}}=6\times {10}^3$