A determinant is chosen at random from the set of all determinant of order 2 with elements 0 or 1 only. Find the probability that the determinant chosen is nonzero.
A
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B
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C
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D
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Solution
The correct option is C A determinant of order 2 is of the form Δ=∣∣∣abcd∣∣∣ It is equal to ad - bc. The total number of ways of choosing a, b, c, and d is 2×2×2×2=16 Now, Δ≠0 if and only if either ad = 1, bc = 0 or ad = 0, bc = 1. But ad = 1, bc = 0 if a = d = 1 and one of b, c is zero. therefore, ad = 1, bc = 0 in three cases. Similarly, ad = 0, bc = 1 in three cases. Therefore, the required probability is 616=38