A determinant of second order is made with the elements $0$ and $1.$ The number of determinants with non-negative values is:

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Solution

The correct option is D 13
There are only three determinants of second order with negative value, $∣ ∣ ∣ \begin{matrix} 0 & 1 1 & 0 \end{matrix} ∣ ∣ ∣, ∣ ∣ ∣ \begin{matrix} 0 & 1 1 & 1 \end{matrix} ∣ ∣ ∣, ∣ ∣ ∣ \begin{matrix} 1 & 1 1 & 0 \end{matrix} ∣ ∣ ∣$
Number of possible determinants with elements $0$ and $1$ are $2^{4} = 16$
therefore, number of determinants with non-negative values is $13.$

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A determinant of second order is made with the elements 0 and 1. The number of determinants with non-negative values is:

The correct option is D 13There are only three determinants of second order with negative value, ∣∣∣0110∣∣∣,∣∣∣0111∣∣∣,∣∣∣1110∣∣∣Number of possible determinants with elements 0 and 1 are 24=16therefore, number of determinants with non-negative values is 13.

A determinant of second order is made with the elements $0$ and $1.$ The number of determinants with non-negative values is: