218

You visited us 218 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Saturation Current

A deuteron of...

Question

A deuteron of kinetic energy 50 KeV is describing a circular orbit of radius 0.5 metre in a plane perpendicular to the magnetic field B . The kinetic energy of the proton that describes a circular orbit of radius 0.5 metre on the same plane with the same B is .?

Open in App

Solution

Suggest Corrections

Similar questions

Q. A deutron of kinetic energy

50 keV

is describing a circular orbit of radius

0.5

metre in a plane perpendicular to magnetic field

\to B

. The kinetic energy of the proton that describes a circular orbit of radius

0.5

metre in the same plane with the same

\to B

Q. A deutron of kinetic energy 50 keV is describing a circular orbit of radius 0.5 m, in a plane perpendicular to magnetic field

\to B

. The kinetic energy of a proton that discribes a circular orbit of radius 0.5 m in the same plane with the same magnetic field

\to B

Q. A deutron of kinetic energy

50 k e V

is describing a circular orbit of radius

0.5 m

in a plane perpendicular to magnetic field

\to B

. The kinetic energy of the proton that describes a circular orbit of radius

0.5 m

in the same plane with the same

\to B

is :

A proton with 1 MeV kinetic energy is moving in a circular path of radius R in a uniform magnetic field. What should be the energy of an α - particle to describe a circle of same radius in the same magnetic field?

Q. A proton carrying

1 M e V

kinetic energy is moving in a circular path of radius

R

in uniform magnetic field. What should be the energy of an

α

-particle to describe a circle of same radius in the same field?

Join BYJU'S Learning Program