Question

A developer has land that has $xfeet$ of lake frontage. The land is to be subdivided into lots, each of which is to have either $80feet$ or $100feet$ of lake frontage. If $\frac{1}{9}$ of the lots are to have $80feet$ of frontage each and the remaining $40lots$ are to have $100feet$ of frontage each, what is the value of $x$?

• A. $400$
• B. $3,200$
• C. $3,700$
• D. $4,400$
• E. $4,760$

Answer 1

Answer: (D)

$4,400$

Total feet $=x$ lots = L $

$\frac{1}{9}$ lots have $80$ feet

$\frac{8}{9}$ lots have $100$ feet $=40$ lots.

$\frac{8}{9}\times L=40\Rightarrow L=\frac{40\times 9}{8}=45$ lots in total.

$5$ lots have $80$ feet.

Total feet $\left(x\right)=5\times 80+40\times 100$

$=4,400$