In achromatic combination, dispersion is zero but deviation is non-zero.
Net deviation is given as: δnet=(μ1−1)A1−(μ2−1)A2⇒2∘=0.5A1−0.6A2 ...(1)
Condition for dispersion to be zero is given as: ω1(μ1−1)A1=ω2(μ2−1)A2⇒0.02(0.5)A1=0.03(0.6)A2
⇒10A1=18A2 ...(2)
From equation (1) and (2):
2∘=A12−A13
∴A1=12∘