A 23 43 13 23b 12 13 13 14

a) 23+ 43= 63=2 13+ 23= #160; 33=1 23 13= 13 43 23= 23 13+ 23= 33=1 b) 12+ 13=3+26= 56 13+ 14=4+312= 712 12 13=3 26 ...

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Byju's Answer

Standard VI

Mathematics

Addition of Fractions

a 23 43 13...

Question

(a)
$\frac{2}{3}$ $\frac{4}{3}$
$\frac{1}{3}$ $\frac{2}{3}$
(b)
$\frac{1}{2}$ $\frac{1}{3}$
$\frac{1}{3}$ $\frac{1}{4}$

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Solution

$a) \frac{2}{3} + \frac{4}{3} = \frac{6}{3} = 2 \frac{1}{3} + \frac{2}{3} = \frac{3}{3} = 1 \frac{2}{3} - \frac{1}{3} = \frac{1}{3} \frac{4}{3} - \frac{2}{3} = \frac{2}{3} \frac{1}{3} + \frac{2}{3} = \frac{3}{3} = 1$
$b) \frac{1}{2} + \frac{1}{3} = \frac{3 + 2}{6} = \frac{5}{6} \frac{1}{3} + \frac{1}{4} = \frac{4 + 3}{12} = \frac{7}{12} \frac{1}{2} - \frac{1}{3} = \frac{3 - 2}{6} = \frac{1}{6} \frac{1}{3} - \frac{1}{4} = \frac{4 - 3}{12} = \frac{1}{12} \frac{1}{6} + \frac{1}{12} = \frac{2 + 1}{12} = \frac{1}{4}$

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(a)23431323(b)12131314

a)23+43=63=213+23=33=123−13=1343−23=2313+23=33=1b)12+13=3+26=5613+14=4+312=71212−13=3−26=1613−14=4−312=11216+112=2+112=14

(a)
$\frac{2}{3}$ $\frac{4}{3}$
$\frac{1}{3}$ $\frac{2}{3}$
(b)
$\frac{1}{2}$ $\frac{1}{3}$
$\frac{1}{3}$ $\frac{1}{4}$