A diagonal of a rectangle is inclined to one side of the rectangle at ${25}^{\circ }$. Find acute angle between the diagonals.

The correct option is B: ${50}^{\circ }$

We know that the diagonals of rectangles are equal and bisect each other.

$\therefore AC=BD$

$\frac{1}{2}AC=$ $\frac{1}{2}BD$ [dividing both sides by $2$]

$OA=OB$ [Since, $O$ is the mid – point of $AC$ and $BD$]

$\angle 2=\angle 1={25}^{\circ }$ [angles opposite to equal sides are equal]

We know that exterior angles is equal to the sum of two opposite interior angles.

In $△AOB,$ we have

$\angle 3=$ $\angle 1+$ $\angle$ 2 [Exterior angle property]

$\therefore$ $\angle 3={25}^{\circ }+{25}^{\circ }={50}^{\circ }$

Hence, the acute angle between the diagonals is ${50}^{\circ }$ .