Question

A diathermic piston divides adiabatic cylinder of volume $V_0$ into two equal parts as shown in the figure.Both the parts contain ideal monoatomic gases. The initial pressure and temperature of gas in left compartment are $P_0$ and $T_0$ while that in right compartment are $2P_0$ and $2T_0$. Initially the piston is kept fixed and the system is allowed to acquire a state of thermal equilibrium.
The pressure in left compartment after thermal equilibrium is achieved is:

• A. $P_o$
• B. $\frac{3}{2}{P}_o$
• C. $\frac{4}{3}{P}_o$
• D. None

Answer 1

Answer: (B)

$\frac{3}{2}{P}_o$

At thermal equilibrium, the presence in both the compartments become equal with the pressure in left compartment increasing to a value equal to that decreasing in right compartment.
The equilibrium value is $\frac{P_0+2P_0}{2}=\frac{3}{2}{P}_0$