Question

A diathermic piston divides adiabatic cylinder of volume $V_0$ into two equal parts as shown in the figure. Both the parts contain ideal monoatomic gases. The initial pressure and temperature of gas in left compartment are $P_0$ and $T_0$ while that in right compartment are $2P_0$ and $2T_0$. Initially the piston is kept fixed and the system is allowed to acquire a state of thermal equilibrium.
The pressure in left compartment after thermal equilibrium is achieved is given?

• A. $P_0$
• B. $\frac{3}{2}{P}_0$
• C. $\frac{4}{3}{P}_0$
• D. None

Answer 1

Answer: (B)

$\frac{3}{2}{P}_0$

Answer B is correct.

At thermal equilibrium, from the given condition the presence in both the compartments of the figure becomes equal with the pressure in the left compartment increasing to a value equal to that of decreasing in the right compartment. The equilibrium value=$\frac{P_0+2P_0}{2}=\frac{3P_0}{2}$.