A diatomic gas (γ=75) is compressed to 132 times of its initial volume adiabatically and reversibly. If its initial pressure is 2P0, its new pressure will be :
A
64P0
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B
128P0
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C
256P0
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D
16P0
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Solution
The correct option is C256P0 We know, For adiabatic process,
P2P1=(V1V2)γ where P1=2P0 initial pressure P2= final pressure V1= initial volume V2= final volume =132V1 γ=7/5 so, P2=P1(V1V2)γ=2P0(32)7/5=256P0.