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Question

A diatomic ideal gas initially at 273 K is given 100 cal heat due to which system did 209 J work. Molar heat capacity (Cm) of gas for the process is:

A
32R
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B
52R
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C
54R
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D
5 R
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Solution

The correct option is D 5 R
From first law of thermodynamics :
ΔU = q+W
and U=nCvT
so,
nCvT=100×4.2209=420209=211Jn×5R2×T=211nT=211×25R
molar heat capacity is given as:
Cm=qnT=420211×2×5R5R

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