CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A diatomic ideal gas initially at 273 K is given 100 cal heat due to which system did 209 J work. Molar heat capacity (Cm) of gas for the process is:

A
32R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
52R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
54R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5 R
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 5 R
From first law of thermodynamics :
ΔU = q+W
and U=nCvT
so,
nCvT=100×4.2209=420209=211Jn×5R2×T=211nT=211×25R
molar heat capacity is given as:
Cm=qnT=420211×2×5R5R

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon