Question

A diatomic molecule has a dipole moment of 1.2D. If the bond distance is $1.0\mathring{A}$, fraction of an electronic charge on each atom is:

• A. $10\%$
• B. $20\%$
• C. $25\%$
• D. $50\%$

Answer 1

Answer: (C)

$25\%$

Electronic charge ${}^{\prime }{e}^{\prime }=\frac{Dipolemoment}{Bondlength}=\frac{1.2\times {10}^{-18}esucm}{1\times {10}^{-18}cm}=1.2\times {10}^{-10}esu$

Now fraction of electronic charge $=\frac{1.2\times {10}^{-10}}{4.8\times {10}^{-10}}=0.25$

$\because$ charge of electron $=4.8\times {10}^{-10}esu=25$% of $e^{-}$

Ans :- Option C.