Question

A diatomic molucule has a dipole moment of 2.4 D. If the bond length is 2 $\mathring{A}$. What fraction of electronic charge exist on one of the poles?

Answer 1

Electronic charge 'e'= $\frac{Dipolemoment}{Bondlength}$

$\Rightarrow \frac{1.2\times {10}^{-18}}{1.0\times {10}^{-0}cm}=1.2\times {10}^{-10}esu$

Thus, fraction of $e^{-}$ charge on each end:-

$\Rightarrow \frac{1.2\times {10}^{-10}}{4.8\times {10}^{-10}}=0.25$