A dice is rolled and a coin is tossed simultaneously. What is the probability of getting a head and an odd number.

\frac{1}{3}

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\frac{1}{4}

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\frac{1}{2}

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\frac{2}{3}

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Solution

The correct option is B $\frac{1}{4}$
Total possible cases: ${H 1, H 2, H 3, H 4, H 5, H 6, T 1, T 2, T 3, T 4, T 5, T 6} = 12$
Total favourable cases: ${H 1, H 3, H 5} = 3$
Probability of getting a head and an odd number $= \frac{3}{12} = \frac{1}{4}$

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A dice is rolled and a coin is tossed simultaneously. What is the probability of getting a head and an odd number.

The correct option is B 14Total possible cases: {H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}=12Total favourable cases: {H1,H3,H5}=3Probability of getting a head and an odd number =312=14

The correct option is B $\frac{1}{4}$
Total possible cases: ${H 1, H 2, H 3, H 4, H 5, H 6, T 1, T 2, T 3, T 4, T 5, T 6} = 12$
Total favourable cases: ${H 1, H 3, H 5} = 3$
Probability of getting a head and an odd number $= \frac{3}{12} = \frac{1}{4}$