A dice is rolled. What is the chance that the upper face will be more than $3$ ?

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Solution

A dice is rolled
Numbers on the dice $1, 2, 3, 4, 5, 6$
Number more than $3 = 4, 5, 6$
Total number of outcomes $= 6$
Possible outcomes $= 3$
Probability of getting more than $3$ on the upper face $= \frac{N u m b e r o f o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s} = \frac{3}{6} = \frac{1}{2}$
Chance of getting 3 on the upper face will be $= \frac{1}{2}$

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