Question

A dice is thrown $20$ times and the outcomes are noted as shown below:

$\begin{array}{ccccccc}\text{Out comes}& 1& 2& 3& 4& 5& 6\\ \text{No. of times}& 2& 3& 4& 4& 3& 4\end{array}$

Now a dice is thrown at random, find the probability of getting:

iii. A number greater than $3$

Answer 1

Find the probability of getting a number greater than $3$

Given:

Total number of possible outcomes $=20$

Number greater than $3$ are $4,5$ and $6$

$\begin{array}{ccccccc}\text{Out comes}& 1& 2& 3& 4& 5& 6\\ \text{No. of times}& 2& 3& 4& 4& 3& 4\end{array}$

From the table,
Number of times $4$ occurred $=4$
Number of times $5$ occurred $=3$
Number of times $6$ occurred $=4$

Number of favorable outcomes $=4+3+4=11$

Probability of getting a number greater than $3$

$=\frac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}$

$=\frac{11}{20}$

Hence, probability of getting a number greater than $3$ is $\frac{11}{20}$.