A dice is thrown 40 times and each time the number on the uppermost face is noted as shown:

Outcome 1 2 3 4 5 6

Number of times 5 6 8 10 7 6

A dice is thrown at random. What is the probability of getting a 5?
(a) $\frac{5}{7}$

(b) $\frac{7}{5}$

(c) $\frac{1}{8}$

(d) $\frac{7}{40}$

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Solution

(d) $\frac{7}{40}$

Explanation:
Total number of trials = 40
Number of times 5 appears = 7
P(getting 5) = $\frac{Number of times 5 appears}{Total number of tr ia ls} = \frac{7}{40}$

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