A dice is thrown once. Find the probability of getting a factor of 6.
1/3
1
2/3
2/5
The sample space is S = {1, 2, 3, 4, 5, 6}; n(S) = 6
Let E be the event of getting a factor of 6.
E = {1, 2, 3, 6}; n(E) = 4
Therefore P(E) = n(E)n(S)= 46= 23