Question

A dice is thrown twice. Find the probability of getting a bigger value on the first throw.

• A. 15/36
• B. 15/31
• C. 21/36
• D. 18/36

Answer 1

The correct option is A

15/36

There are 36 outcomes for rolling a die twice.

Let us first consider the event “Getting the same value” for rolling a die twice. There are 6 favourable outcomes, so the probability is $\frac{6}{36}$.

So, the probability of getting different values on rolling a die twice is 1 - $\frac{6}{36}$ = $\frac{30}{36}$

Of these, getting a bigger value in the first and getting a bigger value in the second are equally likely.

Hence, both these probabilities = $\frac{1}{2}\times \frac{30}{36}=\frac{15}{36}$