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Rolling of Dice Experiment

A dice is thr...

Question

A dice is thrown twice.The probability that 5 will not come up either of the time is

A

\frac{35}{36}

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B

\frac{25}{36}

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C

\frac{1}{36}

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D

\frac{11}{36}

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Solution

The correct option is B $\frac{25}{36}$
Total cases =36
favourable cases =25
So, probability that 5 will not come up either of the time = $\frac{25}{36}$

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Similar questions

Q. Two dice are thrown simultaneously. The probability of obtaining total score of seven is
(a) 5/36
(b) 6/36
(c) 7/36
(d) 8/36

Q. (i) Complete the following table:

Event: 'Sum on $2$ dice'	$2$	$3$	$4$	$5$	$6$	$7$	$8$	$9$	$10$	$11$	$12$
Probability	$\frac{1}{36}$						$\frac{5}{36}$				$\frac{1}{36}$

(ii) A student argues that there are

11

possible outcomes

2, 3, 4, 5, 6, 7, 8, 9, 10, 11

12

. Therefore, each of them has a probability

\frac{1}{11}

. Do you agree with this argument?
Justify your answer.

Q. two dices are thrown simultaneously. What is the probability that

(a). 5 will not come up on either of them.

Q. A dice is rolled twice. Find the probability that
(i)

5

will not come up either time (ii)

5

will come up exactly one time

Q. Two dice are thrown simultaneously. What is the probability that:

(i) 5 will not come up on either of them?

(ii) 5 will come up on at least one?

(iii) 5 will come up at both dice?

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