Question

A dice is thrown twice. What is the probability that the same number will come up either time ?

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Total outcomes = 36 i.e.

(1, 1) , (1, 2), (1, 3) (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Favorable outcomes = 6 i.e. {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}

Therefore probability of same number either time =$\frac{6}{36}=\frac{1}{6}$