Question

A dice is thrown, what is the probability of getting a number which is neither divisible by 2 nor 3?

• A. $\frac{1}{2}$
• B. $\frac{1}{3}$
• C. $\frac{2}{3}$
• D. $\frac{5}{6}$

Answer 1

The correct option is B

$\frac{1}{3}$

The numbers below 6 which are not divisible by 2 or 3 are {1, 5}
Number of favorable cases = 2
Total number of cases = 6
Probability = $\frac{Favorablecases}{Totalnumberofcases}$
= $\frac{2}{6}$
= $\frac{1}{3}$