Question

A die has 6 faces marked by the given numbers as shown below:

The die is thrown once. What is the probability of getting
i) a positive integer
ii) an integer greater than -3
iii) the smallest integer
[4 MARKS]

Answer 1

Concept: 1 Mark
Each subpart: 1 Mark each

Given: A die has 6 faces marked by the given numbers as shown below.

The die is thrown once.
Total number of outcomes = 6
i) Let the event be "a positive integer"
Favourable outcomes are 1, 2, 3
The number of favourable outcomes = 3
$\therefore$ P(a positive integer) $=\frac{3}{6}=\frac{1}{2}$

ii) Let the event be "an integer greater than -3"
Favourable outcomes are 1, 2, 3, -1, -2
The number of favourable outcomes = 5
$\therefore$ P(an integer greater than -3) $=\frac{5}{6}$

iii) Let the event be "the smallest integer"{
Favourable outcomes = -3
The number of favourable outcomes = 1
$\therefore$ P(the smallest integer) $=\frac{1}{6}$