Question

A die has two faces each with number '$1$', three faces each with number '$2$' and one face with number '$3$'. Die is rolled once. The probability of obtaining the number $2$ is:

• A. $\frac{1}{2}$
• B. $\frac{1}{6}$
• C. $\frac{1}{3}$
• D. None of these

Answer 1

The correct option is A $\frac{1}{2}$

$Since$ $three$ $out$ $of$ $six$ $faces$ $have$ $2$ $on$ $them,$ $probability$ $of$ $having$ $2$ $as$ $the$ $outcome$ $=\frac{3}{6}=\frac{1}{2}$